Question

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is :
(i) red
(ii) black

Answer 1

SOLUTION :  

GIVEN : Number of red balls = 3

Number of black balls = 5

Total number of balls in a bag = 3 + 5 = 8

Total number of outcomes = 8

(i) Let E1 = Event  of selecting that a  ball drawn is red

Number of red balls = 3

Number of outcome favourable to E = 3

Probability (E1) = Number of favourable outcomes / Total number of outcomes

P(E1) = 3/8

Hence, the required probability of getting a red ball , P(E1) = 3/8 .

(ii) Let E2 = Event  of selecting that a ball drawn is black

Number of outcome favourable to E = 5

Probability (E2) = Number of favourable outcomes / Total number of outcomes

P(E2) = 5/8

Hence, the required probability of getting a black ball , P(E2) = ⅝ .

HOPE THIS ANSWER WILL HELP  YOU….

Answer 2

Given:

No. of red balls in bag = 3

No. of black balls in bag = 5

1) Probability of getting a Red ball:

Favourable outcomes for getting a Red ball = 3

Total outcomes = 5+3 = 8

P(R) = Favourable outcomes/ Total Possible Outcome

= 3/8
1) Probability of getting a Black ball:

Favourable outcomes for getting a black ball = 5

Total outcomes = 5+3 = 8

P(B) = Favourable outcomes/ Total Possible Outcome

= 5/8

Hope it helps you.