Question

A bag contains 3 red balls and
5 black balls. If one red ball is
drawn at random from the bag, its
probability will be​

Answer 1

Step-by-step explanation:

We Have :-

A bag containing 3 red balls and 5 black balls.

To Find :-

If one red ball is drawn at random from the bag, its probability will be

Formula Used :-

$P \: (E) = \dfrac{number \: of \: favourable \: outcomes}{total \: number \: of \: outcomes}$

Solution :-

$We \: have \: 3 \: red \: balls \: and \: 5 \: black \: ball \\ \\ We \: want \: probability \: of \: 1 \: red \: ball \\ \\ P \: (E) = \dfrac{number \: of \: favourable \: outcomes}{total \: number \: of \: outcomes} \\ \\ P \: (E) = \dfrac{3 \: red \: balls}{3 \: red \: balls + 5 \: black \: balls} \\ \\ P \: (E) = \dfrac{3 }{3 + 5 } \\ \\ P \: (E) = \dfrac{3 }{8}$

$So \: the \: probability \: is \: \dfrac{3}{8}$

Answer 2

Answer:

Given :-

Red balls = 3

Black balls = 5

To Find :-

Probability of getting red

Solution :-

We know that

P(E) = F/T

P = Probability

F = Favourable Outcome

T = Total outcomes

Total outcomes = 3 + 5

P(E) = 3/8

Hence,

• Probability is 3/8