Math, asked by zackaraya01, 9 months ago

A bag contains 3 red marbles and 4 blue marbles.

Two marbles are drawn at random without replacement.

If the first marble drawn is red, what is the probability the second marble is blue?

Answers

Answered by dcmthriveni
5

Answer:

3/4 answer

Step-by-step explanation:

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Answered by SillySam
19

Answer :

2/3

Solution :

  • Number of red marbles = 3
  • Number of blue marbles = 4
  • Total number of marbles = 3+4 = 7

When first marble is taken out ,

  • Total number of marbles = 7-1=6
  • Number of red marbles = 3-1 = 2
  • Number of blue marbles = 4

 \boxed{ \sf{probability =  \frac{favourable \: outcomes}{total \: outcomes} }}

Probability of second marble to be blue = Number of blue marbles / Number of marbles left

= 4/6

= 2/3

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Probability is the chance of getting a certain outcome . The probability of any event may vary from 0 to 1 .

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