Question

A bag contains 3 white, 4 red and 5 black balls. One ball is drawn at random. What is the probability that the ball drawn is neither black nor white? (a) 1/3 (b) 1/4 (c) 5/12 (d) none of these​

Answer 1

Nor black nor white means only red.

E = event = only red

P(E) = (No. of favorable outcomes)/(Total no. of outcomes)

$P(E) = \frac{4}{12} = \frac{1}{3}$

(a) 1/3

Answer 2

Answer:

Nor black nor white means only red.

E = event = only red

P(E) = (No. of favorable outcomes)/(Total no. of outcomes)

P(E) = \frac{4}{12} = \frac{1}{3}P(E)=124=31

(a) 1/3