Question

A bag contains 3 white and 2 black balls.

An other bag contains 5 white and 3

black balls. If a bag is chosen at random

and draw of one ball is made. Find the

probability of that ball being white​

Answer 1

Consider the following events:

E1=Selecting first bag. E2=Selecting second bag , A= ball drawn is white.

Then P(E1)=P(E2)=1/2,

P(A/E1)=3/5

P(A/E2)=2/6

Required probability 

=P(A)=P(E1)×P(A/E1)+P(E2)×P(A/E2)

       =1/2×3/5+1/2×2/6

      = 7/15

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