Question

A bag contains 30 balls numbered 1 to 30 one ball drawn at random find probability that ball drawn is multiple of 5 or 7 and 3 or 7

Answer 1

P ( multiple of 5 or 7 ) = 10÷30=1/3
P ( multiple of 3 or 7 ) = 13÷30=13/30

Answer 2

Answer:

Step-by-step explanation:

total no. of balls p(n) =30

1) multiple of 5 or 7

we know from 1 to 30 there is 10 balls that are 5, 10, 15, 20, 25, 30, 7, 14, 21, 28

so probability that drawn ball is multiple of 5 or 7 =

$\frac{10}{30}\\\\=\frac{1}{3}$

2) multiple of 3 or 7

we know from 1 to 30 there are 14 ball that are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 7, 14, 21, 28

so probability that drawn balii is multiple of 3 or 7 =

$\frac{14}{30}\\\\=\frac{7}{15}$