Question

a bag contains 30 balls numbered from 1 to 30, one ball is drawn at random find the probability that the number of the ball drawn will be multiple of i.)5 or 7 ii.)3 or 7​

Answer 1

• Multiple of 5 or 7

5,7,10,14,15,20,21,25,28,30

10/30 is the probability of multiple of 5 or 7

• Multiple 3 or 7

3,6,7,9,12,14,15,18,21,24,27,28,30

13/30 is the probability of multiple of 3 or 7

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Answer 2

$\bold{TOTAL \: CONDITION = 30}$

◼ 1,2,3,4,5,6,7,8,9,10

◼ 11,12,13,14,15,16,17,18,19,20

◼21,22,23,24,25,26,27,28,29,30}

$\large{1--Multiple \: of \: 5 \: or \: 7}$

▶MULTIPLE OF 5 = 5,10,15,20,25,30 = 6

▶MULTIPLE OF 7 = 7,14,21,28 = 4

$\bold{POSSIBLE \: CONDITION = 10}$

$\boxed{PROBABLITY = \frac{POSSIBLE \: CONDITION}{TOTAL \: CONDITION}}$

$\mathsf{PROBABLITY = \frac{10}{30}}$

$PROBABLITY = \frac{1}{3}$

$\large{1--Multiple \: of \: 3 \: or \: 7}$

▶MULTIPLE OF 3 = 3 ,6 , 9 ,12 ,15, 18 ,21,24,27,30 = 10

▶ MULTIPLE OF 7 = 7,14,21,28 = 4

Since, 21 is multiple of both it will be taken only once.

$\bold{POSSIBLE \: CONDITION = 13}$

$\large \boxed{PROBABLITY = \frac{POSSIBLE \: CONDITION}{TOTAL \: CONDITION}}$

$\mathsf{PROBABLITY = \frac{13}{30}}$

$PROBABLITY = \frac{13}{30}$