A bag contains 4 red balls and 5 blue balls if 3 balls are picked at random what is the probability that two of them are green and one of them is blue color
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Answer:
Ratio of blue:green=5:0
no of balls= 9
P(E)=0/9
=0
since there are no green balls so there cannot be any possibilities...
Please mark me brainliest.
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