Question

A bag contains 4 white, 5 black and 6 green balls. One ball is drawn at random. Find the probability that the drawn ball is (a) Black (b) Green

Answer 1

Answer:

Total outcomes =6+8+5+3=22

Favourable outcomes =6+3=9

∴ Required probability =

22

9

Step-by-step explanation:

please mark it brainliest answer and please don't hesitate to give me a thanks for this answer and follow me also

Answer 2

Answer:

Total outcomes =4+5+6+=15

Favourable outcomes =4+6 =10

∴ Required probability = $\frac{15}{9}$