A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:
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Probability of 1st ball = red is 5/(4+5+6) = 5/15.
P(2nd ball = red) = 4/14 as only 4 red balls remain if 1st ball = red. Out of 14.
P(3rd ball = red) is 3/13.
Answer = 5/15 * 4/14 * 3/13
= 2/91
P(2nd ball = red) = 4/14 as only 4 red balls remain if 1st ball = red. Out of 14.
P(3rd ball = red) is 3/13.
Answer = 5/15 * 4/14 * 3/13
= 2/91
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