Two dice are tossed. The probability that the total score is a prime number is:?
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Answered by
6
Total outcomes=6+6=12
Possible outcomes=5(Prime Numbers Out Of 12)
Probability=5/12 hope this helps u
Possible outcomes=5(Prime Numbers Out Of 12)
Probability=5/12 hope this helps u
Answered by
1
Clearly, n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.
Then E
= { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3),
(5, 2), (5, 6), (6, 1), (6, 5) }
n(E) = 15.
P(E) = n(E)/n(S)
= 15/36
= 5/12.
Let E = Event that the sum is a prime number.
Then E
= { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3),
(5, 2), (5, 6), (6, 1), (6, 5) }
n(E) = 15.
P(E) = n(E)/n(S)
= 15/36
= 5/12.
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