a bag contains 4 white balls and 6 red balls . two draw of one balls each are made without replacement. what is the probability that one is red and the other is white
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Step-by-step explanation:
The probability that the first ball drawn is red is 6/10. The probability that the second ball drawn is white (given that the first ball drawn is red) is 4/9. The joint probability of this scenario is (6/10)*(4/9).
The probability that the first ball drawn is white is 4/10. The probability that the second ball drawn is red (given that the first ball drawn is white) is 6/9. The joint probability of this scenario is (4/10)*(6/9).
Therefore the probability that one ball drawn is red and the other is white is the sum of proabilities of the two scenarios above , i.e. 48/90 = 0.533
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