Question

a bag contains 5 rd balls , 8 white balls , 4 green balls and 7 black balls. if one ball is drawn at random. Find the probability that it is
A)black B)red C)not green ​

Answer 1

Answer:

This answer is only for lucky chances.

So, I guess its red (pls be correct:-) )

Answer 2

Answer:

A) 7/24 B) 5/24 C) 20/24 or 5/6

Step-by-step explanation:

Total number of balls = 24

A) Number of black balls = 7

$probability = \frac{number \: of \: black \: balls}{total \: number \: of \: balls}$

$= \frac{7}{24}$

B) Number of red balls = 5

$probability = \frac{number \: of \: red \: balls}{total \: number \: of \: balls}$

$= \frac{5}{24}$

C) Probability of not getting a green ball i.e getting a ball of colour red, white or black

Number of balls= 5+8+7=20

$probability = \frac{number \: of \: balls \: other \: than \: greem}{total \: number \: of \: balls}$

$= \frac{20}{24} = \frac{5}{6}$