Question

A bag contains 5 red & 3 black balls and the second one 4 red and 5 black balls. One of these
is selected at random and a draw of two balls is made from it. What is the chance that one of
them is red and the other is black?​

Answer 1

Step-by-step explanation:

in first bag probably of red ball

total ball r 5+3 =8

probably of red ball =3/8

in second bag

total balls r 4+5=9

probably of black ball = 5/9

I hope it helps mark as brainliest

Answer 2

Answer:.

red ball =9/17 and black balls=8/17

Step-by-step explanation:

(p) of getting red balls=total red balls /total balls

= 5+4/(5+3)+(4+9)

=9/8+9

=9/17

(p) of getting black Balls=total black/total balls

=3+5/17

=8/17