A bag contains 5 red and 4 green balls and another bag contains 3 red and 7 black balls. If a ball is drawm from each bag. Find the probability that both are different colours
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Answer:
We have,
Bag 1:
Red ball = 5
Green ball = 3
Bag 2:
Red ball = 4
Green ball = 6
Now, according to the question we will have to cases.
1. Probability of getting Red ball from bag 1 and green ball from bag 2 = (5/8) * (6/10) = 30/80
2. Probability of getting Green from bag 1 and Red from bag 2 = (3/8) * (4/10) = 12/80
Therefore, probability of getting Red and Green,
= (30/80) + (12/80) = 42/80 = 21/40.
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