Question

A bag contains 5 red and 6 black balls. In how many ways can 6 ball be selected from 3 balls of each bag

Answer 1

Answer:

There are 5 black and 6 red balls in the bag.

2 black balls can be selected out of 5 black ball in

5

C

2

ways and 3 red ball can be selected out of 6 red balls in

6

C

3

ways.

Thus, by multiplication principle, required number of ways of selecting 2 black and 3 red balls is

5

C

2

×

6

C

3

=

2!3!

5!

×

3!3!

6!

=

2

5×4

×

3×2×1

6×5×4

=10×20=200