a bag contains 5 red balls 4 green balls and 7 black balls one of ball is drawn at random find the probability that it is not Green
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No of red balls = 5
No of green balls = 4
No of black balls = 7
Total no. of balls = 16
P ( green balls ) = 4 / 16
= 1 / 4
P ( not green ball ) = 1 - P ( green ball )
= 1 - 1 / 4
= 4 - 1 / 4
= 3 / 4
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Answered by
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Answer:
THE PROBABILITY OF RED=5
THE PROBABILITY OF GREEN =4
THE PROBABILITY OF BLACK =7
TOTAL PROBABILITY =5+4+7=16
PROBABILITY FORMULA= n(e)/n(s)
PROBABILITY OF RED + PROBABILITY OF BLACK =5+7=12
probability that it is not Green=12/16 OR 3/4
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