- A bag contains 5 red balls, 6 white balls,
7 green balls, 8 black balls. One ball is drawn
at random from the bag. Find the probability
that the ball drawn is (i) white (ii) black or
red (iii) not white (iv) neither white nor black
Answers
Answered by
5
Answer:
i- 6/26
ii- 13/26
iii - 20/26
iv - 12/ 26
hope it is useful to you
Answered by
9
Step-by-step explanation:
total number of balls= 5+6+7+8= 26
1- probability that the ball drawn is white= number of white balls/ total number of balls
= 6/26
= 3/13
2- probability that the ball.drawn is black or red
= number of black and red balls/ total number of balls
= 13/26
=1/2
3- probability that the ball drawn is not white
= number of black.red and green balls/ total number of balls
= 20/26
= 10/13
4- probability that the ball drawn is neither white nor black
= number of red and green balls/ total number of balls
= 12/26
= 6/13
hope it helps you
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