a bag contains 5 red balls 8 white Balls for green balls and 7 black balls if one ball is drawn at random then right probability that is
(1)black
(2) not Green
(3) red
Answers
Answered by
0
1 -7/20
2-not mentioned in question
3-5/20
Answered by
0
Answer:
black ball p(E)=7/20
not green p(E)=1
red p(E)=5/20
Step-by-step explanation:
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