A bag contains 5 red balls and 8 blue balls. It also contains 4 green and 7 black balls. If a ball is drawn at randomly find the probability that it is not green
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probability of getting ball which is not green =ball which is not green/total no. of balls=20/24
scientistSohanKumar:
It will be
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let the sample space be 'S'. n(s)=24
let A be the event that the balldrawn is not green.n(A)=20
P(A)=20/24=5/6
The probability that green ball is not drawn is 5/6
let A be the event that the balldrawn is not green.n(A)=20
P(A)=20/24=5/6
The probability that green ball is not drawn is 5/6
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