in the triangle abc ab:bc:ca =3:4:5 then find the value of sin a and cos a
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sina=p/h=3x/5x
cosa=b/h=4x/5x
cosa=b/h=4x/5x
dhanraj5126:
but the answer given in book is sin a=4/3 and cos a=4/5
the value of sin a is 3/5 and cos a =4/5
there may be a misprint in your book
ok thanks
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this question is not complete give the question correctly
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