A bag contains 5 red balls and some blue balls. If the probability of drawing a
blue ball is double that of a red ball, determine the number of blue balls in a bag....
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Answered by
39
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A bag contains 5 red balls and some blue balls. If the probability of drawing a
A bag contains 5 red balls and some blue balls. If the probability of drawing ablue ball is double that of a red ball
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Let, the number of blue ball be x
Number of red ball = 5
Total number of balls = 5+x
P()=
P()=
_____________________________
P()= 2*P()
_____________________________
But, number of ball cannot be negative.
hence, the number of blue ball is 10
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Answered by
2
Given:
Number of Red balls = 5
P(drawing a blue ball) = 2{ P (drawing a red ball) }
To find:
The number of blue balls in the bag
Answer:
Now,
Let the number of blue balls be x
The total number of balls in the bag = ( 5+x )
And the probability of
▪︎drawing a red ball = 5 / (5+x)
▪︎drawing a blue ball = x / (5+x)
So,
x / (5+x) = 2[ 5 / (5+x) ] {Given}
= x / 5+x = 10 / 5+x (5+x will cancel out)
=> x = 10
Hence, The number of of blue balls in the bag is 10.
Total number of balls are 15 . (5+x)
P(red balls) = 5/ 15
= 1/3
P(blue balls) = 10/ 15
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