Question

A bag contains 5 red balls and some blue balls. If the probability off drawing a blue ball is double that of a red ball, then the number of blue balls in a bag is​

Answer 1

Step-by-step explanation:

the answer is picture

Please make me as brilliant

Answer 2

Answer:

$\sf \underline\red{Correct \: answer \: is \: 10}$

Step-by-step explanation:

$\sf{Let \: number \: of \: blue \: balls \: in \: the \: bag = x}$

$\sf{ Total \: no \: of \: balls \: in \: bag =5+x \: \: [No. \: of \: redball =5)}$

$\sf{Probability \: of \: drawing \: a \: blue \: ball = \dfrac{No. \: of \: blue \: ball}{Total \: no \: of \: ball}}$

$\sf{P(B)= \dfrac{x}{5 + x} }$

$\sf{Probability \: of \: drawing \: a \: red\: ball = \dfrac{No. \: of \: blue \: ball}{Total \: no \: of \: ball}}$

$\sf{P(r)= \dfrac{5}{5 + x} }$

$\sf \blue{Given,}$

$\sf{P(B)=2P(R)}$

$\sf{ \dfrac{x}{5+x} =2( \dfrac{5}{5 + x})}$

$\large \boxed {\mathfrak{ \pink{x=10}}}$

$\therefore{ \underline{ \sf{Hence, \: no. \: of \: blue \: balls \: in \: the \: bag \: =10}}}$

.