Question

A bag contains 5 red smileys, 6 yellow smileys and 3 green smileys. If two smileys are picked at random, what is the probability that both are red or both are green in colour?
A) 7
B) 1/7
C) 3/7
D) 0

Answer 1

Hey mate ^_^

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Answer:
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Given total number of smileys

$= 5 + 6 + 3$

$= 11 + 3$

$= 14$

Now,

Required probability

$= \frac{5C2}{14C2} + \frac{3C2}{14C2}$

$= \frac{10}{91} + \frac{3}{91}$

$= \frac{13}{91}$

$= \frac{1}{7}$

Therefore,

Correct option B) $\frac{1}{7}$

#Be Brainly❤️

Answer 2

hey

here is answer

Given total number of smileys 

$\begin{lgathered}= 5 + 6 + 3 \\\end{lgathered}$

$\begin{lgathered}= 11 + 3 \\\end{lgathered}$

= 14

Now, 

Required probability 

$= \frac{5C2}{14C2} + \frac{3C2}{14C2}$

$\begin{lgathered}= \frac{10}{91} + \frac{3}{91} \\\end{lgathered}$

$\begin{lgathered}= \frac{13}{91} \\\end{lgathered}$

$= \frac{1}{7}$



hope it helps

thanks