Math, asked by gsubrata6712, 20 days ago

A bag contains 5 white, 6 black and 6 yellow balls. 3 balls are drawn at random. Find the probability that
a)all are black
b)exactly 2 yellow balls

Answers

Answered by akshaya830038
1

Answer:

1

Step-by-step explanation:

1

2

will be correct answer not wrong

Answered by RizwanaAfreen
0

Given :

white ball   = 5

Black ball   = 6

Yellow ball =  6

To Find :

The probability that

        a)all are black

        b)exactly 2 yellow balls

Solution:

     Total number of balls = 5+6+6= 17

The total number of ways of selecting 3 balls out of 17 balls is  17 C_{3}

a) The Probability that all are black:

    Number of Black balls                = 6

   The probability that all are black = \frac{6C_{3} }{ 17 C_{3}}

    The probability that all are black = \frac {6*5*4}{ 17*16*15}

    The probability that all are black  = \frac{1 }{ 34}

b)The probability that exactly 2 yellow balls are drawn

       Number of yellow balls         = 6

       Number of non-yellow balls  = 11 ( 5 white,6 black)

The probability that exactly 2 yellow balls are drawn  = \frac{6C_{2} * 11C_{1}  }{ 17 C_{3}}

The probability that exactly 2 yellow balls are drawn   = \frac {(6*5)*(11)}{ 17*16*15}                                        

 The probability that exactly 2 yellow balls are drawn  =\frac{1 1}{ 136}

From the 3 balls drawn at random,

          a)The probability that all are black  is \frac{1 }{ 34}

         b) The probability that exactly 2 yellow balls are drawn  is \frac{1 1}{ 136}

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