A bag contains 5 white, 6 red and 4 green balls. One ball is drawn at random. What is the
probability of getting (1) a red ball (11) a non red ball
Answers
Answer:
a red ball = 6/15
a non red ball = 11/15
Step-by-step explanation:
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Answer:
White
White
White
White 6
White 6Red
White 6Red
White 6Red
White 6Red 9
White 6Red 9Green
White 6Red 9Green
White 6Red 9Green
White 6Red 9Green Total number of balls =5+6+9
White 6Red 9Green Total number of balls =5+6+9 =20
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability =
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total cases
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) =
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 20
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) =
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 20
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 =
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 20
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red)
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red) =
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red) = 20
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red) = 206
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red) = 206
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red) = 206
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red) = 206 =
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red) = 206 = 10
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red) = 206 = 103
White 6Red 9Green Total number of balls =5+6+9 =20(i) Probability = Total casesfavourable cases P(Green) = 209 (ii) P(White or red) = 205+6 = 2011 (iii) P(neither green nor white) = P(Red) = 206 = 103