A bag contains 5 white,7 red,4 black and 2 blue balls,one ball is drawn at random from the bag.what is the probability that the ball is drawn neither white nor black?
Answers
Answered by
1
9/18.So it become 1/2.
Answered by
9
Hey friend ☺️ here is your answer
Total outcomes = 5 + 7 + 4 + 2 = 18
Favourable outcomes of getting a ball which is neither white nor black = 7 + 2 = 9
P(x) = Favourable outcomes / total outcomes
P( getting a ball which is neither white nor black ) = 9/18 = 1/2
Hope this helps you.
Total outcomes = 5 + 7 + 4 + 2 = 18
Favourable outcomes of getting a ball which is neither white nor black = 7 + 2 = 9
P(x) = Favourable outcomes / total outcomes
P( getting a ball which is neither white nor black ) = 9/18 = 1/2
Hope this helps you.
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