Question

A bag contains 5 white and 9 red balls. One ball is drawn at random from the bag. Find the probability of getting
(a) a white ball (b) a red ball.

Answer 1

➡Given

• A bag contains balls as given
• White balls = 5
• Red balls = 9
• In ball is drawn at random from the bag.

➡Required to Find

Probability of balls

➡Solution

Red balls = 9

White balls = 12

Total balls = 9 + 12 = 21

Favourable outcomes = 9

$\sf \: p(red) \: = \dfrac{favourable \: outcomes}{total \: outcomes}$

$\implies \sf \dfrac{ \cancel9}{ \cancel{21}} = \dfrac{3}{7}$

$\sf \: Therefore \: the \: probability \: \: that \: the \: ball \: drawn \: red \: is \: \: \dfrac{3}{7}$

Answer 2

Answer:

$\huge\fbox \pink{answer}$✍

Total balls=15

Black balls =6

Chance of black ball= 6/15

Chance of red ball 9/15.

Chance it will be either red or black: 6/15 + 9/15 = 15/15 or certainty.

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