Question

A bag contains 5 white balls, 7 red balls, 4 black balls and 2 blue balls.A ball is drawn at random from the bag. Find the probability that the drawn ball is (i) white or blue, (ii) neither white nor black. ​

Answer 1

Step-by-step explanation:

Since, total no. of balls = 5+7+4+2 = 18

(i) No. of balls that are white or blue = 5+2 = 7

∴ Required probability =

18

7

(ii) No. of balls that are red or black = 7+4 = 11

∴ Required probability =

18

11

(iii) No. of balls that are not white = 7+4+2 = 13

∴ Required probability =

18

13

(iv) No. of balls that are neither white nor black = 7+2 = 9

∴ Required probability =

18

9

=

2

1

please follow me

Answer 2

Answer:

this is very simple

first of all add the given balls ( blue +red+white+black)

the answer we get after adding is 18 then see the question 1) white or blue ( add both ball no )

7 and total is 18 so the answer is 7/18

and 2) neither white nor black

add balls no except white and black # 9/18