a bag contains 50 balls. some of them are white, blue and red. the number of white balls is 11 times the number of blue balls. the number of red balls is less than the number of white balls. also the number of red balls more than the number of blue balls. if one of the balls is selected at random from the bag what is the probability that it is red?
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Answer:
14 / 50
Step-by-step explanation:
as white balls are 11 times more than blue balls and total balls are 50 so blue balls can be upto 4 only. so white balls become 44. now subtracting both from 50 we get red ball = 2
but red balls are more than blue balls so
now take blue balls = 3
then white balls become = 33 then red balls become 14 which are more than blue but less than white.
here probability of red become 14 / 50
but blue can be 2 then white = 22 and red = 26
this cannot be the condition so red can be 14 only.
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