Question

A bag contains 50 bolts and 100 nuts. Half of the bolts and half of the nuts are rusted. If an

item is chosen at random, find the probability that it is rusted or it is a bolt.​

Answer 1

Answer:

5/6

Step-by-step explanation:

total; 50+100= 150

b=50

n=100

rusted bolts + rusted nuts = 50/2 + 100/2 =  25+50 = 75

P(r) = 75/150

P(b) = 50/150

P(r) or P(b) = 75/150 + 50/150

                 = 125/150

                 =5/6

                 

Answer 2

Total bolts= 50

Rusted bolts=25

Total nuts=100

Rusted nuts=50

Favourable outcomes= 100+25

=125

Total outcomes=50+100

=150

Solution=150÷125

=1.2

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