Question

a bag contains 50 Paisa, 1 Rupee and 2 Rupees coins in the ratio 2:5:8 total amount is Rs 352 find the total numbers of Coins in the bag?​

Answer 1

$Given \: Ratio \:of \:coins = 2 : 5 : 8$

$Let \:the \:ratio \:is 2x : 5x : 8x$

$Total \: amount = Rs \:352$

$\implies 2x \times (50\:paise) + 5x \times( 1 \:Rupee )+ 8x \times (2 \:Rupee ) = 352$

$\implies 2x \times (50\:paise) + 5x \times 2( 50 \:paise )+ 8x \times4 (50 \:paise ) =2 \times 352(50\: paise)$

$\implies 2x + 10x + 32x = 704$

$\implies 44x = 714$

$\implies x = \frac{704}{44}$

$\implies x = 16$

Therefore.,

$Number \:of \:50 \:paise \:coins = 2x \\= 2 \times 16 = 32$

$Number \:of \:1\:Rupee \:coins = 5x \\= 5 \times 16 = 80$

$Number \:of \:2\:Rupee \:coins = 8x \\= 8 \times 16 = 128$

Therefore.,

$\red { Total \:number \:of \:coins \:in \:the \:bag}$

$\green { 50 \:paise \: coins = 32 }$

$\green { 1 \:Rupee \: coins = 80 }$

$\green { 2 \:Rupee \: coins = 128 }$

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