A bag contains 50 paisa, 25 paisa and 10 paisa coins in ratio of 5:9:4, amounting to rupees 206 . find the number of 50 paisa coins
Answers
Answer:
Let the rational between the number of coins be y
Thus, the number of 50p, 25p and 10p coins will be 5y, 9y and 4y
Total value of 50 p coin = value of one coin × number of coins
= Rs 0.50 × 5y = Rs 2.50y
Similarly, total value of 25p coin
= Rs 0.25 × 9y = Rs 2.25y
And total value of 10p coins
= Rs 0.10 × 4y = Rs 0.40y
Total values of all coins put together
= Rs (2.50y + 2.25y + 0.40y) = Rs 5.15y
According to the statement, the total value of all coins is Rs 206
Hence, 5.15y = 206
y = 206/ 5.15
y = 40
The rational is 40
The ratio of 50 p coin is 2.50y, thus
= 2.50 × 40= 100
The ratio of 25 p coin is 2.25y, thus
= 2.25 × 40 = 90
The ratio of 10 p coin is 0.40y, thus
= 0.40 × 40 = 16
Number of 50 p coin = 100/0.50 = 200 Nos.
Number of 25p coin = 90/0.25 = 360 Nos.
Number of 10p coin = 16 /0.10= 160 Nos
Answer the number of 50p,25p and 10p coins in the purse are 200, 360 and 160 coins respectively
Thus, value of 0.50 p, 0.25p and 0.10p coins would be Rs 100, Rs 90 and Rs 16 respectively
Total value = Rs (100 + 90 + 16) = Rs 206
Means answer is correct.
Answer:
200
Step-by-step explanation:
5X×50 + 9X×25 + 4X×10 = 20600 praise
solve to get X =40
hence 50p coins = 40×5 = 200