Question

a bag contains 5green and 7red balls . two balls are drawn. what is the probability that one is green and other is red?
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Answer 1

Question:-

• a bag contains 5green and 7red balls . two balls are drawn. what is the probability that one is green and other is red?

Solution:-

Order is not specified so both green then red and red then green would be winners.

There are 12 balls overall.

Probability of Green,Red: 5/12 x 7/11 = 35/132

Probability of Red, Green: 7/12 x 5/11 = 35/132 It is not just coincidence that these two probabilities are exactly the same.

Answer:-

• 35/132 + 35/ 132 = 70/132 = 35/66 or approximately 53%

I hope it helps...

:D

Answer 2

Answer:-

Green balls are = 7/12

Red balls are = 5/12

Explanation:-

There are 5 green balls and 7 red balls. So, the total number of balls are 12.

Then,

P(the number of green balls)=7/12

P(the number of red balls)=5/12