a bag contains 6 red 3 black and 6 white balls A ball is selected at random from the bag find the probability that the selected ball is 1red or black 2 not black
Answers
Answered by
10
Answer:
1) 3/5
2)4/5
total no of balls=6+6+3=15
no of red and black =6+3=9
probability=9/15=3/5
candy52:
for the second part , no of balls that are not black=6+6=12
probability=12/15=4/5
Answered by
13
Answer:
1) 3/5
2) 4/5
Step-by-step explanation:
To get the probabilities we need to get the total number of balls in the bag.
The total number of balls = 6 + 3 + 6 = 15
Probability of getting red = 6/15 = 2/5
Probability of getting black = 3/15 = 1/5
Probability of getting white = 6/15 = 2/5
We can now answer the questions below :
1) The probability that the selected ball is red or black
= P(black or red) = p(red) + p(black)
= 2/5 + 1/5 = 3/5
2) The probability that the selected ball is not black.
The number of balls that are not black = 6 + 6 = 12
P(not black) = 12/15 = 4/5
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