Question

A bag contains 6 red balls, 8 white balls, 5 green balls and 3 black balls. One ball is

drawn at random from the bag. Find the probability that the ball is :

(i) white (ii) red or black (iii) not green (iv) neither white nor black​

Answer 1

Answer:

means total balls 22

Step-by-step explanation:

1). 8/22

4//11

2) 9/22

3( 11/22

1/2

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Answer 2

Answer:

given

red balls= 6

white balls= 8

green balls = 5

black balls = 3

total balls = 22

Step-by-step explanation:

(I) p( getting a white ball) = no of white/ total no of balls

= 8/22

(ii) red or black

p(taking a red ball ) = 6/22

p( taking a black ball) = 3/22

(iii) not green refered to 22-5= 17

= 17/22

(iv) neither white not black = 22-11 = 11 ( 8 white balls and 3 black balls = 8+3 = 11)

= 11/22