Question

A bag contains 6 red balls and 8 green balls. They are all mixed thoroughly and one ball is drawn at random. Find the probability of getting a)red ball b)green ball.

Answer 1

1) P(getting red ball is)
$\frac{6}{14}$
2) P(getting green ball is
$\frac{8}{14}$
hope it helps!!!!!!

Answer 2

Answer:

Step-by-step explanation:

Red= favourable outcomes /total outcomes =1/6

Green ball =favourable outcomes /total outcomes =1/8