a bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball from the bag is twice that of a red ball. Then find the number of blue balls in the bag
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Answer:
X=10.
Step-by-step explanation:
number of red balls = 5
number of blue balls = x
n(s)=5+x
•p(E)=n(e)/n(s)
p (getting red balls) =5/ 5 + 6
p (getting blueborne) =x/ 5 + 6
p (blue balls) = 2x (red balls)
x / 5 + x = 2× 5 / 5 +x
the 5+x is equal in both at denominator so it is cancelled.
then,
x=2×5
x=10.
hence,
number of balls in the back =10.
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