Question

A bag contains 6 red balls and some blue balls. if the probability of a drawing a blue ball from the bag is twice that of a red ball, find the number of blue balls in the bag.

Answer 1

SOLUTION :  

Given : Number of red balls = 6  

Let the probability of getting red balls ,P(E) = x  

Probability of getting a blue ball , P(E¯) = 2x  

The sum of all the probabilities of all possible outcomes of experiment is 1.

P(E) + P(E¯) = 1

x + 2x = 1

3x = 1  

x = ⅓  

Hence, the probability of getting red ball is ⅓ .

Probability = Number of favourable outcomes / total number of outcomes

P(red ball) = Number of red ball / Total number of balls

⅓ = 6 / Total number of balls

Total number of balls = 6 × 3 = 18  

Total number of balls = 18 balls  

Number of blue  balls = Total number of balls - Number of red balls  

Number of blue  balls = 18 - 6 = 12  

Hence, the number of blue  balls  in the bag is 12 .

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Answer 2

Hello mate

Given:-

RED BALLS = 6

LET BLUE BALLS BE = B

TOTAL NUMBER OF BALLS = BLUE + RED
= 6 + B

P(E)of blue balls are double than that of red balls.

P(E)Blue= 2×P(E)Red
B/B+6=2×6/B+6


B = 12

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