A bag contains 6 red balls some blue balls .if the prbablity of drawing a blue ball is twice the probability of drawing red balls find number of blue balls
Answers
Answered by
201
Given Red balls = 6
Let Blue balls = B
Total balls = B + 6
P(E)of blue balls is double than red balls
then
P(E) blue = 2 x P(E) red
B / B + 6 = 2 x 6 / B + 6
B = 12
Therefore ther are 12 blue balls
Let Blue balls = B
Total balls = B + 6
P(E)of blue balls is double than red balls
then
P(E) blue = 2 x P(E) red
B / B + 6 = 2 x 6 / B + 6
B = 12
Therefore ther are 12 blue balls
Answered by
75
See this is a very easy one...
Red ball = 6nos. = p(e) = 6/x
Blue ball = 2 (p(red)) = 12 nos.= 12/x
So sum = x = 12 + 6
x = 18
No of blue ball =12
Red ball = 6nos. = p(e) = 6/x
Blue ball = 2 (p(red)) = 12 nos.= 12/x
So sum = x = 12 + 6
x = 18
No of blue ball =12
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