A bag contains 6 red chips numbered 1 through 6, respectively, and 6 blue chips numbered 1 through 6, respectively. If 2 chips are to be picked sequentially from the bag of 12 chips, without replacement, what is the probability of picking a red chip and then a blue chip with the same number?
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total chips =12
red chips with same no. =1
probability =1/12
similar probability of blue chip = 1/12
red chips with same no. =1
probability =1/12
similar probability of blue chip = 1/12
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probability of red chip = no. of favourable outcomes ÷ total no. of outcomes
= 1/12
probability of getting blue chip = no.
of favourable outcomes÷total no. of outcomes
= 1/12
= 1/12
probability of getting blue chip = no.
of favourable outcomes÷total no. of outcomes
= 1/12
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