A bag contains 6 white and 9 black balls. Four balls are drawn at a time find the probability for the first draw to give 4 white and the second to give 4 black balls, when the balls are not replaced before the second draw.
Answers
Answered by
12
Dear Student,
Please find below the solution to the asked query:
4 W+9B=15 balls(i) balls are replaced before the second draw Required Probabilty= 6C4 15C4× 9C4 15C4(i) balls are not replaced before the second draw Required Probabilty= 6C4 15C4× 9C4 11C4 [11 because 4 balls are drawn]
Hope this information will clear your doubts about this topic.
Similar questions