a bag contains 7 red 5 blue and 3 green balls one ball is drawn at random from the bag find the probability that the ball drawn is: i) a red ball ii) a green ball iii) not a blue ball
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(i) possible outcomes =7+3+5=15
favorable outcomes =7
p(red ball) = 7/15
(ii) possible outcomes =15.
favorable outcomes =3
p(green ball) = 3/15=1/5
(iii) possible outcomes =15.
favorable outcomes =7+3=10.
p(not a blue ball) =10/15=2/3
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