A bag contains 7 red balls, 4 black balls and 3 white balls. A ball is drawn from the bag at random. Find the probability of getting (i) a black ball (ii) a red ball (iii) a black or white ball
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Answer:
First for the denominator 7+4+3 = 14.
So,
(i): 4/14 = 2/7
(ii): 7/14 = 1/2
(iii): 4/14 + 3/14 = 7/14 = 1/2
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