Question

A bag contains 75 red balls 25 green ball and 90 blue ball a bag is taken out from the big at random what is the probability that this ball is not a blue ball

Answer 1

Answer:

100/190is the answer

Answer 2

Answer:

$\huge{\boxed{\boxed{\sf{P(E)=\frac{10}{19}}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

□No of red balls in bag=75

□No of red balls in bag=75□No of green ball in bag=25

□No of red balls in bag=75□No of green ball in bag=25□No of blue ball in bag=90

□No of red balls in bag=75□No of green ball in bag=25□No of blue ball in bag=90□Total number of balls in bag=190

$probability \: of \: getting \: not \: a \: blue \: ball \\ p(e)= \frac{number \: of \: events \: outcome}{total \: number \: of \: balls} \\ p(e) = \frac{190 - 90}{190} \\ \: \: \: \: \: \: \: \: \: = \frac{100}{190} \\ \: \: \: \: \: \: \: \: \: = \frac{10 }{19}$

$\huge{\boxed{\boxed{\sf{P(E)=\frac{10}{19}}}}}$