Question

a bag contains 8 black and 4 white balls. If 5 balls are drawn at random, find the chance that three of them are black?

Answer 1

Step-by-step explanation:

Total balls in the bag =8+5=13

Let S be the event of drawing 2 balls from 13 balls. n(S)=

13

C

2

Let E be the event of drawing 2 white balls from 5 white balls. n(E)=

5

C

2

∴P(E)=

13

C

2

5

C

2

=

13×12

5×4

=

39

5

.

Answer 2

Answer:

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Step-by-step explanation:

total number of Sample space = 12C5.

No. of way to draw 2 red balls = 4C2

No. of way to draw 3 white balls = 8C3.

Total number of ways to draw 2 red and 3 white balls = 4C2 * 8C3.

Probability that 2 red and 3 white balls are drawn is

= (4C2*8C3)/12C5

= (4*3/2*1)*(8*7*6/3*2*1)*(5*4*3*2*1/12*11*10*9*8)

= 14/33