Question

A bag contains 8 milk and 9 dark chocolates. A sweet is selected at random. What is the probability of choosing: P(milk) = P(not milk) =

Answer 1

P(milk) = No of milk chocolate/ total no of chocolate

=8/17

P(not milk) = No of not milk chocolate or dark chocolate/ Total no of chocolate

=9/17

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Answer 2

Answer:

Step-by-step explanation:

Total chocolates = 9+8 =17

P(milk) = No. of milk chocolates/Total no. of chocolates(Sample Space)

=8/17

P(not milk) = 9/17. Since P(not milk) = No.of dark chocolates/Total no. of chocolates (Sample Space)

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