a bag contains 8 red, 6 white and 4 black balls . a ball is is drawn at random from the bag. find the probability that the ball drawn is (a) red or white (b) not black ( c) niether white nor black
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A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is
(i) red or white (ii) not black (iii) neither white nor black
November 22, 2019avatar
Apoorva Deb
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ANSWER
Total no. of balls in the bag is 18 (8 red, 4 black and 6 white)
Solution(i):
No. of red or white balls in bag is 14 (8 red and 6 white)
Therefore,
14
C
1
( Selecting 1 out of 14 items) times out of
18
C
1
( Selecting 1 out of 18 items) a red or white ball is picked.
Let E be the event of drawing a red or white ball from bag
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
18
C
1
14
C
1
=
18
14
=
9
7
Solution(ii):
No. of non-black balls in bag is 14 (8 red and 6 white)
Therefore,
14
C
1
( Selecting 1 out of 14 items) times out of
18
C
1
( Selecting 1 out of 18 items) a non-black ball is picked.
Let E be the event of drawing a non-black ball from bag
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
18
C
1
14
C
1
=
18
14
=
9
7
Solution(iii):
No. of neither black nor white balls in bag is 8 (8 red balls)
Therefore,
8
C
1
( Selecting 1 out of 8 items) times out of
18
C
1
( Selecting 1 out of 18 items) a neither white nor black ball is picked.
Let E be the event of drawing a neither white nor black ball from bag
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
18
C
1
8
C
1
=
18
8
=
9
4
Answer:
a.14/18
b.14/18
c.8/18