Question

A bag contains 9 milk and 5 dark chocolates.
A sweet is selected at random p(milk) p(not milk)

Answer 1

Total number of outcomes = 9+5 = 14
P(milk) = 9/15
P(not milk) =5/14

:)

Answer 2

Answer:

M=9;

C=5;

T=(M+C)=(9+5)=(14);

Step-by-step explanation:

P(M)=(M/T)=(9/14)

P(N M)=P(C)=(C/T)=(5/14)