Question

A bag contains 9 red balls and 6 green balls. A ball is drawn from the bag without looking into the bag. Then what is the probability of getting a green ball?​

Answer 1

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number of red balls in bag = 9

number of green balls in bag = 6

total balls in the bag = 9+6 = 15

$p = \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes}$

there are 6 green balls in the bag..

so if A ball is drawn from the bag without looking into the bag...then probability of getting a green ball is..

$\huge \: p = \frac{6} {15} = \frac{2}{5}$

hence, probability of getting green ball is 2/5

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probability of getting a red ball is..

$\huge {p = \frac{9}{15} = \frac{3}{5} }$

hence, probability of getting green ball is 2/5

and getting a red ball is 3/5

Answer 2

Answer:

ABOVE ANSWER IS CORRECT